How do I declare inout arguments in C#?

Question:How do I declare inout arguments in C#??

Answer: </P><P align=justify>The equivalent of inout in C# is ref. , as shown in the following </P><P align=justify>example: public void MyMethod (ref String str1, out String str2) </P><P align=justify>{</P><P align=justify>...</P><P align=justify>}</P><P align=justify></P><P align=justify></P><P align=justify>When calling the method, it would be called like this: String s1;</P><P align=justify>String s2;</P><P align=justify>s1 = "Hello";</P><P align=justify>MyMethod(ref s1, out s2);</P><P align=justify>Console.WriteLine(s1);</P><P align=justify>Console.WriteLine(s2);</P><P align=justify></P><P align=justify>Notice that you need to specify ref when declaring the function and calling it.

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